Question

Q1: The van't Hoff equation in chemical thermodynamics relates the change in temperature (T) to the change in the equilibrium constant (K) given the standard enthalpy change (A) for the process. If the enthalpy change of reastion ig asumed to be constant with tempernture the van't Hoff equation may be written as: K2) = _(1-1 Plot Ink, versus T, for the reaction N2+3112艹2 NH, from 300 K to 400 K (10 K intervals). Label thex-axis, y-axis and give a title, n, “ 2-4 へ^ Given 11ス =13.272 = 8.3 14 J/mol·K In K1 Ti-298.15K at Find Inks at TOOK 1, 416

solve this question by using MATLAB.

Answer 1

% Van't Hoff equation
% equalibrium constant vs Temperature
clc
clear all
lnK1 = 13.272;
delta_H0 = -92220;
T1 = 298.15;
R = 8.314;
T2 = 300:10:400;
lnK2 = lnK1 - delta_H0*(1./T2 - 1/T1)/R; % expression to be plotted
plot(T2,lnK2,'*-');
xlabel('Temperature T_{2} ( K )');
ylabel('ln(K_{2})');
title('Variatin in equalinrium constant with temperature');
ylim([0 max(lnK2)]);
grid on

2 2 Ди。--92220 J/mol k13.29 2 T298.IS K "T2 = 300:10:400 K