Question

a. obtain the quartiles b. determine the interquartile range c. find the five-number summary d. identify potential outliers,

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Answer #1

Solution(a)
First sort the data from smallest to largest data value as follows:
45,48,64,70,73,74,74,78,78,79,79,80,80,80,80,80,80,81,82,82
n = 20
Quartile 1 or Q1 can be calculated as
Q1 = (n+1)/4 = (20+1)/4 = 5.25th value i.e. 5th value is 73 and 6th value is 74 so 5.25th value is 73+0.25*(74-73) = 73.25
Q2 or Median = (n+1)/2 = (20+1)/2 = 10.5th value i.e. 10th value is 79 and 11thy value is 79 so median is 79
Q3 = 3*(n+1)/4 = 3*(20+1)/4 = 15.75th value i.s. 15th value is 80 and 16th value is 80 so Q3 = 80
Solution(b)
Interquatile range can be calculated as
IQR = Q3 - Q1 = 80 - 73.25 = 6.75
Solution(c)
five number summary can be calculated as
Minimum = 45
Q1 = 73.25
Median = 79
Q3 = 80
Maximum = 82
so five number summary is 45,73.25,79,80,82
Solution(d)
Lower fence = Q1 - 1.5 * IQR = 73.25 - 1.5*6.75 = 63.125
Upper fence = Q3 + 1.5*IQR = 80+1.5*6.75 = 90.125
Any value which is not between 63.125 and 90.125 than this valus is outlier.
So outliers are 45 and 48
Solution(e)
82 44

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