Solution(a)
First sort the data from smallest to largest data value as
follows:
45,48,64,70,73,74,74,78,78,79,79,80,80,80,80,80,80,81,82,82
n = 20
Quartile 1 or Q1 can be calculated as
Q1 = (n+1)/4 = (20+1)/4 = 5.25th value i.e. 5th value is 73 and 6th
value is 74 so 5.25th value is 73+0.25*(74-73) = 73.25
Q2 or Median = (n+1)/2 = (20+1)/2 = 10.5th value i.e. 10th value is
79 and 11thy value is 79 so median is 79
Q3 = 3*(n+1)/4 = 3*(20+1)/4 = 15.75th value i.s. 15th value is 80
and 16th value is 80 so Q3 = 80
Solution(b)
Interquatile range can be calculated as
IQR = Q3 - Q1 = 80 - 73.25 = 6.75
Solution(c)
five number summary can be calculated as
Minimum = 45
Q1 = 73.25
Median = 79
Q3 = 80
Maximum = 82
so five number summary is 45,73.25,79,80,82
Solution(d)
Lower fence = Q1 - 1.5 * IQR = 73.25 - 1.5*6.75 = 63.125
Upper fence = Q3 + 1.5*IQR = 80+1.5*6.75 = 90.125
Any value which is not between 63.125 and 90.125 than this valus is
outlier.
So outliers are 45 and 48
Solution(e)

a. obtain the quartiles b. determine the interquartile range c. find the five-number summary d. identify...
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can someone please help solve this problems. I don't know how to
find the mean and standard deviation, and the outliers in the data.
Thank You !
2. (12 pts] During his 20 seasons in the National Hockey League, Wayne Gretzky scored 50% more points than anyone who ever played professional hockey. He accomplished this amazing feat while playing in 280 fewer games than Gordie Howe, the previous record holder. Here are the number of games Gretzky played during each...
Can someone help with this problems please
1. (10 pts] Suppose that for a given term, data is collected on the types of courses that SPSCC students take with an interest in online and evening courses. Answer the following questions using the distribution of students below. Online Course No Online Course Totals Evening Course 28 42 70 No Evening Course 82 200 282 Totals 110 242 352 a. What is the probability a student is taking an online course? b....