Question

Module 6: Has anyone seen Fermi Worksheet. Concept Map: Energy dependence of average electron energy vs doping density and temp. N 12 112 _NO-N A + +n? p=n/n = NA N-ND D +n 2 n=n,e-E)/ p= n,e-E)KT E,-E = Tln(n/n, ) = -kTin(p/n,) To Do: 1) Determine Er-Ei for Np=1E+15Pcm at 300K, assume n=1.5E+10cm 2) Determine Er-E for Na=1E+15Pcmat 300K, assume n=1.5E+10cm. You should assume or look up value for k and that in each case the dopant is present in large majority ... at least 3-5 orders of mag.. Be sure to show all of your work.

Answer 1

In the problem given that , in qua na ND - NA 2 ) ę 0 na ni CEf-E;) iki p= 0; 8Ct; -EP) IKS Epzef Krlo (Mmi) = -K11n (Plni) Given that, No = 1x1019 cm3 m= 1:57100cm3 lat 300K) we whare to find out Ef-E; from the expression, Ep-E; = kg hn[*] Already we know that at 300 K) KJ = 26 mev. .: 8-67 = 0.026 in Ghis ) = 0.283ev | Eq- Ej 2 0.3ev

10 Given that NAS ixed 5 cm 3 EN9; = | sxi docm3 we have to find out Ep-E; = ? from the expression TELE; = -KiT in [ Most to E-€; 34 -0.28ev H. Ef-E; 20.300 Lindar - Corn) altas