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QUESTIONS For MM: GD queuing system with 2 servers of service rate =40 customers per hour per server and arrival ratei - 45 c
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Answer #1

Arrival rate = λ = 45 per hour

Service rate = µ = 40 per hour

Traffic intensity = ρ = (λ/ µ) = (45/40) = 1.125

N = 2

Probability P0

P_{0} = \frac{(1-\rho )}{1-\rho ^{N+1}}

P0 = (-0.125/(1-1.4238) = 0.0295

Effective Arrival rate = λeff = λ(1-PN) = λ(1-P0ρN)

λeff = 45 x [1 – (0.0295 x 1.125 ^2)] = 43.3198

please upvote for my answer. Thank you so much

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