A device used in radiation therapy for cancer contains 0.17 g of cobalt-60 (59.933 819 u). The half-life of this isotope is 5.27 yr. Determine the activity (in Bq) of the radioactive material.
half life = ln(2)/k
k = ln(2)/half life = ln(2)/(5.27 x 365 x 24 x 3600) = 4.170693152 x 10-9 /s
now no. of molecules = (0.17/59.933819) x 6.023 x 1023 = 1.708401062 x 1021
activity = 4.170693152 x 10-9 x 1.708401062 x 1021 = 7.12521661 x 1012 Bq
A device used in radiation therapy for cancer contains 0.17 g of cobalt-60 (59.933 819 u)....
A device used in radiation therapy for cancer contains 0.25 g of cobalt-60 (59.933 819 u). The half-life of this isotope is 5.27 yr. Determine the activity (in Bq) of the radioactive material. Provide units please
A device used in radiation therapy for cancer contains 4.70×10-1 g of cobalt 2760Co (59.9333819 u). The half-life of 2760Co is 5.57 yr. Determine the activity of the radioactive material.
A device used in radiation therapy for cancer contains 8.00x10-1 g of cobalt 2760 Co (59.9333819 u). The half-life of 2760 Co is 3.47 yr. Determine the activity of the radioactive material. Submit Answer Tries 0/10 This discussion is closed. 45
(#22) Cobalt-60 is a radioactive isotope that is commonly used
for cancer radiation therapy. The cobalt-60 atom decays to the
stable nickel-60 atom, releasing a beta particle (electron) and
energy in the form of gamma rays:
If you captured the energy from the decay of a 1.19 g pellet of
isotopically pure cobalt-60, how long could you run a 60.0 W light
bulb? In hours
The relevant masses are as follows:
Gamma rays are massless.
60Co-PoNi + β + γ...
Cobalt-60 is a radioactive isotope that is commonly used for cancer radiation therapy. The cobalt-60 atom decays to the stable nickel-60 atom, releasing a beta particle (electron) and energy in the form of gamma rays: 60Co→60Ni+β+γ If you captured the energy from the decay of a 1.34 g pellet of isotopically pure cobalt-60, how long could you run a 60.0 W light bulb? The relevant masses are as follows: Substance Mass (g/mol) 60Co 59.933819 60Ni 59.930788 β 0.000549 Gamma rays...
1) Cobalt – 60, with a half-life of 5 years, is used in cancer radiation treatments. If a hospital purchases a supply of 30.0 g, how much would be left after 15 years? ______________ 2)Iron-59 is used in medicine to diagnose blood circulation disorders. The half-life of iron-59 is 44.5 days. How much of a 2.000 mg sample will remain after 133.5 days? ______________ 3) The half-life of polonium-218 is 3.0 minutes. If you start with 20.0 g, how long...
A 5.0 mL sample of cobalt-60 used in cancer therapy contains 2.00 mCi. How many becquerels are present? (Hint: notice that you have 2 milliCuries not Curies)
1. Cobalt 60 is commonly used as a source in industrial radiography (nondestructive testing of steel products by imaging with gamma radiation). A typical Co source is 100 Curies. Given a half-life of 5.27 years: (a) Calculate the mass of Co needed for a 100 Ci source (Atomic mass = 59.9338 g/mole). (b) If the source is abandoned in a warehouse for 22 years, how many half-lives have elapsed? (c) How much activity remains?
What is the activity of the sample in Bq?
Cobalt-60, which undergoes beta decay, has a half- life of 5.26 yr. N = 3.14x1013 B-particles SU Previous Answers All attempts used; correct answer displayed Part B What is the activity of the sample in Bq? t V AC o XD x x x XI .X.10 > . Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining
Modeling radioactive decay in pennies
MODELING RADIOACTIVE DECAY WITH PENNIES ADVANCED STUDY ASSIGNMENT MODEL 2: RADIONUCLIDE HALF-LIFE The time required for half of a sample of a radionuclides (radioactive isotopes) to decay is called the half-life (units of time). Table 2 below illustrates the half-lives of several radioisotopes and the Table 2: Half-lives of some Radioisoto barium-131 carbon-14 chromium-51 cobalt-60 iodine-131 uranium-238 Radiation Half-life 11.6 days 5730 yrs 27.8 days 5.3 yrs 8.1 days 4.47. 109 yr Application detection of...