2)
From the plot of demand vs time period we see that there is a trend in the data
The seasonality is that the demand drops after every 10 time periods
A r squared value of 0.477 implies that timeperiod can only explain 47.7% of demand
The graph between time period and ADV implies that the forecast is more reliable and there is a satisfactory approximate linear relation between the 2 variables
A r squared value of 0.6630 also implies that there is a linear relation between the 2 variables and time period can explain 66.30% of ADV variable
The graph between time period and DIFF implies that the there is no linear relation between the 2 variables
A r squared value of 0.1816 also implies that there is extremely weak linear relation between the 2 variables
.
The graph between time period and AIP implies that the there is no linear relation between the 2 variables
A r squared value of 0.0845 also implies that there is extremely weak linear relation between the 2 variables
This linear relation is even more weak than the relation between time period and DIFF
The graph between time period and PRICE implies that the PRICE remains almost constant with respect to time period
A r squared value of 0.1474 also implies that there is extremely weak linear relation between the 2 variables
3)
By looking at the DIFF vs demand we see that there is not much fluction in DIFF with respect to demand
The difference is a maximum of 1 positive or negative unit in DIFF
By looking at the ADV vs demand we see that there is a linear increase in Demand as ADV increases
The R squared value is 0.61 which indicates positive linear relation
Looking at the AIP vs demand we see that there are many values of demand at particular points of AIP
The R squared value of 0.08 also implies that there is weak linear relation and the relation may be non linear
Price vs demand graph implies that the price does not vary significantlt
4)
ADV,DIFF,PRICE AND PERIOD all these variables have r>0.5 hence strong relation
ie all these variables can explain the demand variable significantly
ADV has r-0.79 which is the strongest out of the above variables
5)
The MAD defines the variability of the data
Since the 3 month MAD is less than 6 month MAD
The 3 month values are more accurate
6)
We see that at a alpha of 0.9 we get the least MAD ie 0.6049
2- Make time series scatter plots ofall five varables (five graphs) Insert trend line, equation, and...
Here are the graphs.
instrument should have an absorbance reading of zero when there is no CuS04 present. Print copies of the graph for you and your partner to submit with your lab reports. Calculate the concentration of the unknown using the equation for the line. emros Concentration (M) Absorbance 0.5 1.005 0.3 0.704 0.617 0.25 0.1 0.291 0,05 0.131 0.513 Concentration VS Absorbance 1.2 y 2.1773x R2 0.9566 1 e4e4eeresases4s4 0.8 0.6 0.4 0.2 0.4 0.5 0.6 0.1 0.2...
The following are graphs from a full data collection run, using the wheel sensor of an ioLab device Wheel - Position (100 Hz) At: 0.66000 s με 0.247 m-0: 0.20 m 1.6 a: 0.16 ms s: 1.00 m/s 1.0 E 0.8 0.6 0.4 0.2 0.0 12 Time (s) 10 Rezero sensor Wheel Velocity (100 Hz) 0.66000 s μ: 0.989 m/s-0: 0.50 m/s 2.0 a: 0.65 m , s: 2.56 m/s* (r: 1.00) 1.2 0.8 S 0.6 0.4 0.2 0.0 10...
6.Use Exponential smoothing forecasts with alpha of 0.1, 0.2, ..., 0.9 to predict March 2019 demand. Identify the value of alpha that results in the lowest MAD. 7.Find the monthly seasonal indices for the demand values using Simple Average (SA) method. Find the de-seasonalized demand values by dividing monthly demand by corresponding seasonal indices. 8.Use regression to perform trend analysis on the de-seasonalized demand values. Is trend analysis suitable for this data? Find MAD and explain the Excel Regression output...
Question 3
Sample Data and Graphs Solution A Reaction Time Reaction Rate (sec) Experiment 0.1 M KIO, (sec) Water 1 50 mL 150 mL 17 0.0606 7 100 mL 100 mL 0.125 3 25 mL 175 mL 33 0.0303 4 20 mL 180 mL 45 0.0222 80 mL 120 mL 10 0.100 25 sec (predicted) 26 sec (actual) Challenge! 33 mL. 167 mI. 50 40 30 20 10 C 50 100 150 C Volume of KIO, (mL) 0.16 0.12 R...
Please help I am completely confused, I included the 2
graphs needed for this post lab. Thank you!
Postlab Assignments . (a) Using your own standard curve, the line equation you generated and Beer's law equation Equation 1) calculate the molar absorpivity (e) of blue dye. For all your measurem cuvette used is 1.00 cm. Use this as the value of b in Equation 1 ents, the size of (b) Using Beer's law equation again, what does a high value...
price time month day year
149.3999939 1 01 02 13
146.5 2 01 03 13
147.3499908 3 01 04 13
150.3999939 4 01 07 13
148.1499939 5 01 08 13
147.8999939 6 01 09 13
149.6499939 7 01 10 13
153.3499908 8 01 11 13
153.3000031 9 01 14 13
152.5 10 01 15 13
153 11 01 16 13
155.5 12 01 17 13
156.3000031 13 01 18 13
148.5999908 14 01 22 13
150.3999939 15 01 23 13...
3. Plot the graphs Temp(s) versus 1 Veos 8 (10%) 1.2 I 1 0.8 0.60 0.4 0.2 0 0 0.5 1 1.5 2 2.5 1 4. Determine graphically the slope of the function Texp(s) versus- (2%) Vcos e 2 5. Using the result of the previous question and equation Lefr = g slope 2.0 to calculate the effective length Leff of the pendulum. 6. Use the result of previous question and the formula (3) and given data m = (150...
need help with 1-4 ANALYSIS
F vs T^2 0.034 0.033 0.032 0.031 0.03 0.029 0.028 0.027 0.026 0.025 26.6 26.4 26.2 25.6 25.8 25.4 25.2 TA2 F vs 1/TA2 0.034 0.033 0.032 0,031 0.03 0.029 0.028 0.027 0.026 0.025 0.0376 0.0378 0.038 0.0382 0.0384 0.0386 0.0388 0.039 0.0392 0.0394 0.0396 1/T^2 26 r vs TA2 0.9 0,8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 65 50 45 40 35 30 TA2 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1...
this is a really long assignment and I need help
Question 1: Wendy's Happy Homes Inc manufactures Home Appliances. Monthly sales of Wendy's Washers and Dryer Sets for a nine month period were as follows: MONTH Washer and Dryer Sales 490 480 450 500 480 470 490 520 530 January February March April May June July August September Forecast October sales using 1) A four-month moving average 2) a six-month moving average 3. Compute the MAD for each forecast method...
IB math studies
1. Ten students were asked for their average grade at the end of their last year of high school and their average grade at the end of their last year at university. The results were put into a table as follows: Student High School grade, University grade, y 90 3.2 2.6 75 80 3.0 70 95 3.8 85 90 3.8 2.8 70 95 85 3.0 3.5 10 Total 835 30.4 (a) Given that s, 8.96, sy-0.610 and...