Question

use superposition method to solve this problem. thanks!

453 10.4 ANALYSIS OF FRAMES: NO SIDESWAY (0.001286) SE 161 2 Example 2: For the beam shown below, find all reactions. E and I are constant. Determinancy 0.5 k/ft 100k-ft naltres !3n 573 20, @ Find reactions wing Force Method 20 th 20 A Remove redundant reaching Tv. TVB=0 Tvero By & Cu * Apply unit loads you removed

Answer 1

Force method's Principle of virtual wook, applying amit load at B and c then calculating deflection - at B&C compatibility condition AB=0 , AC=O . - AR= rm mau EI m&m are moments due to enternal force and unit load Irespectively o calculating AB 0.5Klft mm look for CB 201B Tey 201 tulº Ft osuç 201 m= 100 + Cyin - 9054.2 m= 100 + Cyin -0.2542

for BA o su <20) m = 100 + By u + Cy (u 120) – 015124 - 05X20 (u} \) me 100 + By u + Cyfu+201 -0.252²-102-100 13 By r t Cy(u+20) -0.254² - lou applying unit load at B for AB & att to ABAC - 8' c 4 = 4 ५ for CB m=0 for (B m=-14=-2 for BA m=-1:2=-2 for BA m=-1 (1720) m = -(4+20) 1. 1.

DB=0 = 1 DO C100 + Cy. 4 -0.2522)0 du + 7 EI ut Cyut20) -0.25u²-10u) (W du Ő L EI 3 0= - 3000 By - 20000 cy +8000 =0 By +25cy = = 0 t 0 of lyin-012522) (-udy S EI + Cy (u+20) -0.254² - 1ou) (-(4+20)dy =0 EI -10000 - 8000 (y + -20000 By - 56000 G +90000 =0 20000 By +64000 ly = 240000 By + 3.2cy = 12 - © ea ② -ca o (3.2-215) Cy = 11 Cy= 15.71 kips By = 12 - 312815.7) By= -38127K

0.5krfl rmmm 11 201 glookaft 1572K 20.27k 201 - MA Ay equilibrium {fyzo equation Ay = 0.5x40 + 38.27 -15172 Ay= 4255 K | - MA - 100 to.5X40X20 +38.27X20 - 40X15172 = 0 TMA = 4366 kaft / Em=0

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