Homework Answers
Sampling Distribution:
X ~ N(55,17/1001/2) or N(55,1.7)
Assuming an average of 6000/100 = 60lb per bag
We find P(X>60).
P(X>60) = 1 – P(X<60) = 1 – P(z<(60-55)/1.7) = 1 – P(z<3.3) = 1 - 0.9996 = 0.0004 or 0.04%
Hence, the probability that total weight is more than 6000lbs is 0.04%
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