Question

It takes 25 N to compress a spring a distance of 30 cm. That compressed spring then has a 3kg block placed in contact with it. The spring is released, causing the 3 kg block to accelerate along a frictionless floor. After leaving the spring, the 3kg block continues moving on the frictionless floor until it collides with and sticks to a 5kg block, initially at rest. What is the spring constant of the spring?

Answer 1

Here,

force , F = 25 N

distance ,x = 30 cm = 0.30 m

m1 = 3 Kg

m2 = 5 Kg

let the spring constant is k

for the spring , force = spring constant * x

F = k * x

25 = k * 0.30

k = 83.33 N/m

the spring constant of the spring is 83.33 N/m