Question

20. The figure below shows a cross section through a very large nonconducting slab of thickness d and uniform volume charge density p > 0. The origin of the x axis is at the centre of the slab. (a) Use symmetry considerations to show that the electric field inside and outside the slab has the form E = E(x) i, where E(-x) = -E(x). (b) Use Gauss's law to find the electric field E produced by the slab as a function of x inside the slab (-d/2 SXS +d/2) and (c) outside the slab (x = -d/2 and x 2 +d/2). d/2

Answer 1

Soln 9) Sina the lab is Very large hence at any point P the Y-component ef akctnc field wl be gut conalledbecaue fhee are Aame amoun f charge above aigin (yand blow ) hich cuil cancel each other) Hence will only x-oMpon ent uryi ve (b.) COnrider the gausya n urace Ahown aboye In this cas flur through upp es face but gin ce there antwo faces Eat 2Ea

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Volume anclosed by gaurtian and Aurface hence from gauaa'n law 2Ea2 for out aide (b but charg thcloned atdp Volume hence E = Pd 2E

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