Question

1. Give a possible set of quantum numbers for an electron in a 4p orbital. (Short Answer) Be careful that you read this question carefully so that you understand what it means! 2. Explain why there is no 2d orbital. (This is practice to see how essay questions work!) 3. Which has the longer wavelength, light of frequency 93.9 MHz or light of frequency 93.9 kHz? (I wanted to use multiple choice for this, but Blackboard needs at least 4 choices, so it is again short answer format. You can just insert the frequency and the units for your response.) 4. Which has the lower frequency, light with photons of 4.0x10-19J or light with photons of 4.0x10-18J in energy? (Same deal as number 3; use one of the Tx buttons in the middle of the Tools Bar to get the superscripts)

Answer 1

t. Electron in AP orbited. Possible quantum number: Principle quantum number ) (b): 4 Azimme that quantum number(s) 2 (for P) Magnetic quantum number (M): +1 O -2 (my one) Slin quantum number(s): +²2,-/2 (any one) 2. Why is there and no ad osksital ? I for any priniple quantum No on, maximum azinethol quantum no. (l) is not. So, for no 2 lie for 2P). l values are out only representing s & p on forn, there should be n? subshell, each containing two electrons. So for no 2, toke no of subshell, 22 4 I

1 Among until 4 one is contained is sorsikal & 3 P. Actually, the angular momentum for azimuthat quant un no 1.2 would be too high to be Contained withane in alotet oskills with no 2.

ve frequency. - 3. The Energy Ef photon is given by hy Planck's constant E2hr an e velocity of ligent, constant 2) EL V x a ware length 7 So, photons of higher energy & photons of higher frequency =photons of brown worst looge sa shorter wavelength Box photons of lower energy a lower frequency a longer wavelength be light of frequency 93.9 kltz will have longer wavelength 4. Similar to 3 which in which everything is already explained, right with photons 4.0x 2013 of will have have lower frequency