a)
V = potential difference across each capacitor = 11.3 Volts
Q = charge stored = 4.60 x 10-6 C
Capacitance is given as
C = Q/V = (4.60 x 10-6)/11.3 = 0.41 x 10-6 F
b)
equivalent capacitance is given as
Ceq = C1 + C2 + C3 = C + C + C = 3 C = 3 (0.41 x 10-6) = 1.23 x 10-6
c)
The Voltage drop remains same
Three identical isolated capacitors, each with capacitance C, are connected in parallel, with a 11.3 V...
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A potential difference V = 4.200×102V is
applied to two capacitors connected in series. One capacitor, C1,
is 4.60 ?F and the other, C2, is 7.50 ?F.
The charged capacitors are disconnected carefully from each
other and from the battery. They are then reconnected, positive
plate to positive plate and negative plate to negative plate, with
no external voltage being applied. What is the charge on the
positive plate of C1?
What is the potential difference across C1?
What is...
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