In order to make 25 mL of an 80 ppm solution, what volume of the 1000 ppm solution would be needed?
The volume of 1000 ppm solution needed = (25 ×80) / 1000 = 2mL
So 2mL solution of 1000 ppm will be needed.
In order to make 25 mL of an 80 ppm solution, what volume of the 1000...
Part A: A solution of 100 ml of 500 ppm quinine solution was prepared this more concentrated solution was used to prepare a desired 5ppm quinine solution. How much solid quinine dihydrate (MW= 782.92 g/mol) will be needed to prepare the 500 ppm quinine solution, as well as the volume of 500 ppm quinine solution needed to make the 5ppm solution. Part B: If 61.1mg of quinine sulfate dehydrate was used what is the actual concentration in the solution ?
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