Archer A has a success rate of 70% and archer B has a success rate of...
Archer A has a success rate of 70% and archer B has a success rate of 60%. An experiment consist of having A try one to hit a balloon, If A fails, then B also gets one try. If the target is hit, what is the probability it was hit by A? I got 35/41, but the correct answer is 35/44, please explain.
Homework Answers
Step 1:
P(Target is hit) = P(A success) + [P(A Fail & B Success) = 0.70 +(0.30X 0.60)
= 0.70 + 0.18 = 0.88
Step 2:
P(A success) = 0.70
Step 3:
Let
X = The target is ht by A
Y = The target is hit
By Multiplication Theorem:
P(X/Y) = P(XY)/P(Y)
= 0.70/0.88
= 35/44
So,
Answer is:
35/44
=
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