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Find the support reaction at B pointing normal to the inclined surface (up and to the left is assumed positive) when w = 28.4 kN/m. Enter result in kN units. 4 4 m し 150 4 m 362.9000

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By ge propertier RB ve 5 HB انم) = Un = 3 RB Ho 2 12 45 RB Now from equation 3 3 2 UB + HB = 465.5 2x 33 kB t as RB = 465.5 6

Support reaction at B Normal to inclined surface is 232.75 KN

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