Question

a. What is the pH of 16.13 L solution if 19.89 g of sodium hydroxide are dissolved inside?

b. What is the pH of a 0.045 M HCl solution?

Answer 1

(Answer a) Given volume of Naoh solution 16.13 L weight of Naoh dissolved 19.899m. Gram. molecular weight of Nadt = 40gm concentration of NaoH Solution Number of moles of Naoh volume in L Wt Gm.wt 16-13 L 19.89/40 16.132 0:49 (d 16.132wers = 3:08x10 - 2 mol.lit concentration of NaoH solution 3.08X2012 Mol litt TOSScanned with CamScanner

7log (OH-] not [OH-] 3.08x10-2 Mele litt РОН a - log (3-08X10-2] 3.08 = 2-log 2-0.488 lo poh loslu pH + polt = 14 auton PH 14-151 pH = 12.49 solution =12.49 The pH of the b ) Given concentration of Hel = bus 0.04SM (H+) in concentration = 0.045 M = 4.5X10-2M lasscanned with CamScanner

PH - logo lo(H+) 4.5 X10-2 -log 10 4.5 2-log 2-0.6532 PH = 1.346 The pH value of 03045 M HU 1:34 Scanned with CamScanner