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CO(g) + Cl2(g) <==-=> COCI2(8) AH = 58 kJ Determine Kp at 500°C if the pressure is in atm and Kc is 5.55 x 1010 A 5.82 x 10-5
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cOcg) + CbCg) = Cocl, C4) SH=58KJ Here -na-n, h = no of product = Il code) = 1-2 ng No. of reactant = -1 = 2 (co, 2) ке Ang =I hope, you will understand the solution. Keep Learning.Good Luck

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