Question

27. A 2.0-m wire segment carrying a current of 0.60 A oriented parallel to a uniform magnetic field of 0.25 T experiences a force of what magnitude? a. 0.30 N b. 6.7 N c. 0.15 N d. zero 28. A horizontal wire of length 3.6 m carries a current of 6.0 A and is oriented so that the current direction is 50-S of W. The Earth's magnetic field is due north at this point and has a strength of 0.14 × 10-4 T. What is the size of the force on the wire? a. 1.6 x 10N b. 0.28 x 10 N C. 1.9 ×10-4 N d. 2.5 x 10 N

Answer 1

27) l = 2m I = 0.60 A B = 0.25 T Theta = 0^degree F = l(I times B) F = l I B sin theta = 0 N sin 0^degree = 0 28) theta = 90^degree + 50^degree = 140^degree I = 6 A L = 3.6 m B = 0.14 times 10^-4 T F = l(I times B) = l I B sin theta = (3.6)(6)(0.14 times 10^-4) sin 140^degree = (3.024 times 10^-4)(0.64278761) = 1.9 times 10^-4 N