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3. A stone is thrown straight upward with a speed of 20m/s. It is caught on its way down at a point 5.0m above where it was t
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2= 20m/s hmax = ? chmen 1h=sm Q = 0 20² u²-2ghman o² = 20²-2glimax toman = 20² 2g 200 9.8 himax = 20.41 m hi hmax-h - 20.41-56 from @ Vh=? q = 38 ms hence, when it was caught vh=1438m/s

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