Question

Test 11 Spring 2018 NYIT Programming CSCI-125-MO3 Prof. F. Fischman Name: 1. Consider the method do Task defined below. public static int doTask (int(a) int index 0; int soFarw1; int count=1: for(int k-1; kca.length; k++){ if(a[k]==a[k-1] count++; if(count>soFar) soFar-count; Indexek else! count=1; return a[index]; When the following code segment is executed, Int[] arr={1, 2, 3,3,3,3, 4, 2, 2, 2, 2, 2, 2, 2,5, 6, 6, 6, 6, 6, 6, 4, 7, 8); System.out.println(do Taskarr)): what is printed to the screen? Why? a. 1 b. 2 c. 6 d. 7 e. 24 2. Assume that the following declarations have been made. int() A={1, 2, 3, 4, 5, 6, 7, 8); int[] B-{4, 5, 6, 7, 8); Also, assume that the method printContents is defined with the following header and works as specified in the comment. //Prints the contents of array arr to the screen. public static void printContents(int[] arr)

Answer 1

✔Solution (1)

Output is -> 2

Reason:-.>This function searches the most frequent number in a sequence like in the following list of numbers.

the most frequent number found in the list of numbers is 2 finds seven times which is the most frequent number in a sequence.

public class Main {
public static void main(String[] args)
{
int[] arr ={1,2,3,3,3,3,4,2,2,2,2,2,2,2,2,5,6,6,6,6,6,6,4,7,8};
System.out.println(doTask(arr));
}

/**
* This function search the
* most frequent number
* like in
* the following list of numbers
* @param a
* @return most frequent number found in the
* list of numbers
* like 2 finds seven times which is most
* frequent number
*/
public static int doTask(int [] a)
{
int index=0;
int soFar=1;
int count=1;
for (int k = 1; k <a.length; k++) {
/**
* If number is equal
* to previous number
*/
if(a[k]==a[k-1])
{
//update counter
count++;
/**
* if count is greater than
* soFar
*/
if(count>soFar)
{
//soFar equals to count
//assign how many duplicates find in
// a sequence
soFar = count;
//Update index to
//index of most frequent
// value
index = k;
}
}
/**
* If number is not equal
* to previous number
* initialize count to 1
*/
else
{
count=1;
}
}
return a[index];
}
}

✔Solution (2)->

//Simple Print

public class Main1 {
public static void main(String[] args)
{
int[] A = {1,2,3,4,5,6,7,8};
int [] B ={4,5,6,7,8};
//call function
printContents(A);
printContents(B);
}
public static void printContents(int[] arr)
{

for (int i = 0; i <arr.length ; i++) {
System.out.print(arr[i]+", ");

}

System.out.print("\n");
}
}

//Output

| 1, 2, 3,4,5,6,7,8, 4,5,6,7,8,

//Java Code to Print in Brackets

public class Main1 {
public static void main(String[] args)
{
int[] A = {1,2,3,4,5,6,7,8};
int [] B ={4,5,6,7,8};
//call function
printContents(A);
printContents(B);
}
public static void printContents(int[] arr)
{
System.out.print("[");
for (int i = 0; i <arr.length ; i++) {
System.out.print(arr[i]);
if((i+1)<arr.length)
System.out.print(", ");
}
System.out.print("]\n");

}
}

//Output

"C:\Program Files\Java\jdk1.8.0_221\bin [1, 2, 3, 4, 5, 6, 7, 8] [4, 5, 6, 7, 8]

//If you need any help regarding this solution......... please leave a comment...... thanks