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Question 13 4 pts Z-scores A variable is normally distributed, with mean 118 and standard deviation 30. What is the Z-score w
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Question (13) Given, l= 118 os 30 i) when x= 100 then Z-score is, X-4 100 T8 30 I-score - 0.6 |z-scorel = 0.6. Z=1.5, the I-susing std Normal rable we gel - P(6osas 160) 0.9192 -0.02659 0.8926 P ( 605 xs 160) = 0.8926 P ( x 7, 130) 1 - PCXS130) = 1-

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