Question

2000 N 3000 N 30 2 Fig. E.5. 19 Fig. E.5.20 5.19 A strut AC hinged at A is held in the horizontal position by a string passing over its free end as shown in Fig. E.5.19. One end of the string is attached to the wall and the other end supports a weight P. Determine the tension in the string and the force in the strut. Neglect the weight of the strut. Ans. T 2 P: S 3 P (compression) nt at a ioint in a truss is shown in Fig. E.5.20. Determine the values of

question 5.19....i need answer

Answer 1

The tension T produced in the string will have 2 components i.e. vertical component and horizontal component.

The vertical component of tension will be equal to weight P at point C and with horizontal component of tension, it will apply force on strut.

So if T is tension of string, then the horizontal component of this tension is given by .

And the vertical compoent of tension is given by $T \sin 30 = T/2$

Since vertical component of this tension handles weight P, therefore

$T/2 = P \Rightarrow T=2P$

And force on strut is applied due to horizontal component of tension equal to $T \cos 30 = T\sqrt{3}/2 = 2P\sqrt{3}/2 = P\sqrt{3}$

Please comment for any clarification