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Data al 1. Determining the calorimeter constant Data (a) Mass of empty Styrofoam cups (b) Mass of cups + 70 ml water Trial 1
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can Answer. RT . Calculations. Terial-1 .1 . Tecial 2 ca) mass of cool = (b) - ca) = (6) - (a) . water in st =(76.25-7. 6.42g

i Temp. Change of cool water in caloucemeter (A Tew = Tef - Tid) = (440+273) K. - (21.0 +2+3) K. 1 = (317-294)K = +23k. = (39

98.829 * 4:2 = 28. 168x4.2 Il/ g/Klx1-60K) . () calculate heat Lose - by hol- water! AHHW - MHW.CC. ATH &(-55 *) = = 6,657.42

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