


l put kinetic energy of 1 equal to kinetic energy of 2. and it didnt work...
A proton is released from rest at the positive plate of a parallel-plate capacitor. It crosses the capacitor and reaches the negative plate with a speed of 5.50×104 m/s . What will be the proton's final speed if the experiment is repeated with double the amount of charge on each capacitor plate?
Will upvote on three accounts if you provide a good walkthrough
for both.
A proton is released from rest at the positive plate of a parallel- plate capacitor. It crosses the capacitor and reaches the negative plate with a speed of 120,000 m/s. What will be the proton's final speed if the experiment is repeated with double the amount of charge on each capacitor plate? 120,000 m/s 240,000 m/s 170,000 m/s 85,000 m/s O 60,000 m/s
Find the speed of an electron that has a kinetic energy of 2.07
eV. 1 eV= 1.602 x 10^-19 J. Answer in units of m/s.
Calculate the speed of a proton with a kinetic energy of 2.07
eV. Answer in units of m/s.
A parallel-plate capacitor has a capacitance Co. A second
parallel-plate capacitor has plates with twice the area and twice
the separation. What is the capacitance of the second
capacitor?
Calculate the energy stored in a 27.3 uF...
I. A proton in a certain particle accelerator has a kinetic energy that is equal to 3.421 times its rest energy. What is the momentum of the proton as measured by a physicist working with the accelerator? (c = 3.00 x 108 m/s, mproton = 1.67 * 10-27 kg)
1) A 11.0-V battery is connected to a 4.40-μF capacitor. How much energy is stored in the capacitor? J 2) Calculate the speed (in m/s) of an electron and a proton with a kinetic energy of 1.10 electron volt (eV). (The electron and proton masses are me = 9.11 ✕ 10−31 kg and mp = 1.67 ✕ 10−27 kg. Boltzmann's constant is kB = 1.38 ✕ 10−23 J/K.) hint: Use the conversion 1 eV = 1.60 ✕ 10−19 J. (a) an electron? m/s...
Calculate the speed (in m/s) of an electron and a proton with a kinetic energy of 1.90 electron volt (eV). (The electron and proton masses are me = 9.11 ✕ 10−31 kg and mp = 1.67 ✕ 10−27 kg. Boltzmann's constant is kB = 1.38 ✕ 10−23 J/K.) (a) an electron m/s (b) a proton m/s (c) Calculate the average translational kinetic energy in eV of a 3.19 ✕ 102 K ideal gas particle. (Recall from Topic 10 that 1...
A proton ( m=1.67 × 10 -27 kg) is accelerated to a kinetic energy of 200 MeV. What is its speed at this energy? A-1.70 × 108 m/s B-9.79 × 107 m/s C-2.47 × 108 m/s D-6.25 × 108 m/s
1. A uniform electric field of magnitude 364 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 2.80 cm. (a) What is the work done by the field on the electron? J (b) What is the change in potential energy associated with the electron? J (c) What is the velocity of the electron? magnitude m/s direction 2. Calculate the speed (in m/s) of an electron and a proton with a...
1) A uniform electric field of magnitude 411 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 2.70 cm. (a) What is the work done by the field on the electron? (b) What is the change in potential energy associated with the electron? (c) What is the velocity of the electron? magnitude ms? direction ? (+x, -x, +y, -y) 2) A 11.0-V battery is connected to a 4.40-μF...
030 (part 1 of 2) 10.0 points A proton in a cyclotron is moving with a speed of 3.27 x 10 m/s in a circle of radius 0.704 m. 1.67 x 10-27 kg is the mass of the pro- ton, and 1.60218 x 10-19 C is its fundamental charge. What is the magnitude of the force exerted on the proton by the magnetic field of the cyclotron? Answer in units of N. 031 (part 2 of 2) 10.0 points What...