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Suppose that a red die and a green die are tossed and the numbers on the sides that face upward are observed (a) What is the
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Answer #1

and e d one 9reen touing dies one Two are (a) Con Si8t oevent Sanpe Space S= . (a) (A2) (23)(a. u) (ais) (a) (2,1) (2,2) 3,3)

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Answer #2

SOLUTION ;


a.


We may get sum of 9 of numbers on the face upward of red and green die,

In the following outcomes)


(Red, green) : (3, 6), (6,3), (4,5), (5,4) 


P(3, 6) = P(6,3) = P(4, 5) = P(5, 4) = 1/6 * 1/6 = 1/36


P( sum =  9) 

= P(3, 6) + P(6,3) + P(4, 5) + P(5, 4) 

= 1/36 + 1/36 + 1/36 + 1/36

= 4/36

= 1/9 

So, probability that the sum of numbers is 9 = 1/9 (ANSWER).


b.


P(sum < 5)


Following possible outcomes are there to get sum < 5 :


(1, 1), (1, 2), (2, 1), (2, 2), (3, 1) , (1, 3) 

Each outcome has probability = 1/6 * 1/6 = 1/36

So, P( sum < 5) 

= 6 outcomes * P(each outcome)

= 6 * 1/36

= 1/6


So, probability that the sum of numbers is less than 5 = 1/6 (ANSWER).


answered by: Tulsiram Garg
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