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Image for An electron s released from rest in a weak electric field given by E = -1.10 x 10^10 N/C J. After the electron
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Answer #1

Net Force is Fnet = Fe+Fg

Fe = q*E = 1.6*10^-19*1.1*10^-10 = 1.76*10^-29 N in Y-direction


Fg = m*g = (9.11*10^-31*9.8) = 89.278*10^-31 N in the -Y-direction


Fnet = (176*10^-31)-(89.278*10^-31) = 86.722*10^-31 N

Work done by the net force = change in kinetic energy

Fnet*S = 0.5*m*v^2

86.722*10^-31*1.9*10^-6 = 0.5*9.11*10^-31*v^2

v = 6.014 mm/s

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