Question

k 9 x 109 Nm"/C2, e-± 1.602 x 10-19 C, F-qE ; E-kg/?, V = kq/r 1· Three charged particles q1, q2 and q3 are arranged on three corners of a rectangle as shown in the diagram below. The rectangle has dimensions 15.0 cm by 8.0 cm. The values of charges are as indicated. Calculate the electrosatic potential difference between points A an given that point B is 5.0 cm from A, the top left corner. 5cm q3 = 8.2 μ C 8.0 cm 3.0 μ C q2 15 cm oc oro located 40 cm apart.

Three charged particles q1,q2 and q3 are arranged on three corners of a rectangle as shown in the diagram below. The rectangle has dinensions 15cm by 8cm the values of th charges are as indicated. Calculate the electrostatic difference

Answer 1

potential due to a point charge at distance r is given as

V = k q / r

Net potential at A:

VA = [ (9 x 10^9) (-5.7 x 10^-6) / (0.08)] + [ (9 x 10^9) (8.2 x 10^-6) / (0.15)] + [ (9 x 10^9) (3 x 10^-6) / sqrt(.08^2 + 0.15^2)]

VA = - 641250 + 492000 + 158823.5

VA = 9573.5 volt

At B:

VB = [ (9 x 10^9) (-5.7 x 10^-6) / sqrt(0.08^2 + 0.05^2)] + [ (9 x 10^9) (8.2 x 10^-6) / (0.10)] + [ (9 x 10^9) (3 x 10^-6) / sqrt(.08^2 + 0.10^2)]

VB = - 543779 + 738000 + 210834.6

VB = 405055.6 volt

VB - VA = 395482 Volt Or 395.5 kV