Question

Question 29 (1 point) Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to find the probability of successes given the probability p of success on a single trial. Round to three decimal places. n=12, 5,P= 0.25 oa 0.103 Ob 0.027 0.082 od 0.091

Answer 1

Solution

Given that ,

p = 0.25

1 - p = 1 - 0.25 = 0.75

n = 12

x = 5

Using binomial probability formula ,

P(X = x) = ((n! / x! (n - x)!) * px * (1 - p)n - x

P(X = 5) = ((12! / 5! (12 - 5)!) * 0.255 * (0.75)12 - 5

=  ((12! / 5! (7)!) * 0.255 * (0.75)7

= 0.103

Probability = 0.103

option a. is correct