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Let f(x) = 19 +a (3kx) with f(0) = 26 and f(8) = 586. Find a and k and then find f(2). The value of a is . (Type an integer o
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f(x) = 19 + al gk x) fo) = 26 flo) = 19+ ax f g ko) 26 = 19+9 (:30 = 1) 26 = 19ta 3) Q = 7.Now, f(x) = 586 19+ 7xgKx8 – 586 → 7x gfk = 567 38 - 567 - 81 & 86=4 k = 13 Now, x x 78 x + +61 = (sof x 8 xt + 61 = 8xt +61

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