02/9/2018 10:55 PM。0/5 Question 1 of 10 For the reaction shown here the equilibrium concentrations were...
For the reaction shown here 2H2g O the equilibrium concentrations were found to be [H2O]= 0.250 M H21-0.580 M [02]:0.750 M What is the equilibrium constant for this reaction? Number
For the reaction 8 H,S(g) = 8H2(g) + S3(g) the equilibrium concentrations were found to be [H,S] = 0.250 M, [HQ] = 0.430 M, and (Sg] = 0.750 M. What is the equilibrium constant for this reaction? Kc =
For the reaction 2H,O(g) = 2H,(8) +0,(9) the equilibrium concentrations were found to be [ H0] -0.250 M, [H,! = 0.510 M, and (0,1 = 0.800 M. What is the equilibrium constant for this reaction? Kog
For the reaction 2H2O(g)−⇀↽−2H2(g)+O2(g) the equilibrium concentrations were found to be [H2O]=0.250 M, [H2]=0.340 M, and [O2]=0.750 M. What is the equilibrium constant for this reaction?
For the reaction shown here 4PH3(g) —> 6H2(g) + P4(g) the equilibrium comcentrations were found to be [PH3] = 0.250 [H2] = 0.600 [P4] = 0.750 What is the equilibrium comstant for this reactiln?
For the reaction 2 H2O(g) + 2 H2(g) + O2(g) the equilibrium concentrations were found to be [H,0) = 0.250 M, [H2) = 0.520 M, and [0,1 = 0.800 M. W equilibrium constant for this reaction? Kon II
For the reaction 2H2O(g)−⇀↽−2H2(g)+O2(g)2H2O(g)↽−−⇀2H2(g)+O2(g) the equilibrium concentrations were found to be [H2O]=0.250 M,[H2O]=0.250 M, [H2]=0.490 M,[H2]=0.490 M, and [O2]=0.750 M.[O2]=0.750 M. What is the equilibrium constant for this reaction?
For the reaction 8H2S(g)−⇀↽−8H2(g)+S8(g)8H2S(g)↽−−⇀8H2(g)+S8(g) the equilibrium concentrations were found to be [H2S]=0.250 M,[H2S]=0.250 M, [H2]=0.460 M,[H2]=0.460 M, and [S8]=0.750 M.[S8]=0.750 M. What is the equilibrium constant for this reaction?
Question 5 1 pts For the reaction 2 A = B, the equilibrium concentrations are as follows: [A] -0.056 M and [B] = 0.12 M. Calculate the equilibrium constant (Keg) for the reaction. O 2.6 x 10-2 38 2.1 O 0.26
Question 10 1 pts For the reaction Cu2S(s) =2Cu* (aq) +52-(aq), the equilibrium concentrations are as follows: (Cut) = 1.0~10-5 M, [52-)- 10 x 10-2 M. The equilibrium constant is: 1.0 x 107 1.0 x 10-12 O 1.0x 10 % 1.0 x 107.