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In Canada, do young males (Y) weigh more than older males (O) on average? To investigate this question, weights of fifteen ma
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Answer #1

df = n_1 + n_2 - 2 = 15 + 15 - 2 = 28

  Test Statistics

Since it is assumed that the population variances are equal, the t-statistic is computed as follows:

t = \frac{\bar X_1 - \bar X_2}{\sqrt{ \frac{(n_1-1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2}(\frac{1}{n_1}+\frac{1}{n_2}) } }

t = \frac{ 85.4 - 78.6}{\sqrt{ \frac{(15-1)15.7^2 + (15-1)19.5^2}{ 15+15-2}(\frac{1}{ 15}+\frac{1}{ 15}) } }

t = 1.052

The p-value is p = 0.1509

a) is the correct answer

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