Question

5. A hawk flying at 15 m/s at an altitude of 180 m accidentally drops its prey. The parabolic trajectory of the falling prey is described by the equation y180- 45 until it hits the ground, where y is its height above the ground and is the horizontal distance traveled in meters. Calculate the distance traveled by the prey from the time it is dropped until the time it hits the ground. Express you answer correct to the nearest tenth of a meter. Hint: Your integral will require a substitution to bring it into a table form.

Answer 1

J-186-会 Seeppose J=o. then 180- 20 - -160 9 -8100 = JSIO xc90 The distance traveled is the arc length pm Too 0 。 款 = (iso-圣) -- [最) ear | Melongth b = | J +對女

peet X= 45 fant, then doc= 45 sectat Imitol-430 -) $antzo tant0=120 x=90 - $51ent=90 Blant-e al zranen henra) Z en4cy L SH fon't usedHot intronca) . Sect) (sect) at tance !?: it! tama Free plank Sect of -45 [sect tent +\m/seot 4 rant 1] = [sec (tenka) farctandcm) +m/seafaret - (Seco temo + Misecotteno)7 1 zate [sec(tambi).4 +In/ secchama) +41 | 8, 20- 1 m. The=209.1m

LE JI+ uzete Hen du eta dhe X=4 =) 434 4 120) 120 Lal Shu malu Situe du care au site tę lnlu +9wu-] -45 [(2S16 +164+1876) -Coto) = 45 (207+M(4+177)? TL 3 2091m