Question

7. The block on the ramp shown is being pulled using the rope shown. (i) For the x-y axes shownlnotone of yourown choosing), which choices best represent the x & y components of the force by the rope on the box? Circle the letter for ALL choices that apply. +x U) 刁 (i) What is the direction of the Force by the Earth on the Block? (b) (c)し (d) (ii) Which of the following are valid ways to find the x-component of the Force by the Earth on the Block (Fee) using the coordinate system shown (not one of your own choosing)? (a) (b)it equals sin θ. It equals cos θ. (c) it equals Fe cos θ. (d) it equal Fes sin e. (iv) Which of the following are valid ways to find the Weight force acting on the block? Circle the letter for ALL choices that apply. (a) It equals g, or 9.8 m/s (b) It equals 9.8 N/kg. (c) It equals the mass times g (d) It equals I(G Mearth m )/ (Rearth)'1. (e) It equals the mass of the block. (1 None of these. (v) Assuming that the rope does not lift the box off of the surface, what can be said about the Normal force (b) It is equal to the weight of the block. (c) It is equal to the mass of the block. by the surface on the block in the situation above? Circle the letter for ALL choices that apply. (a) It is zero. (d) It is the same size as the y-component of the force by the earth on the block. (e) It is the same size as the x-component of the force by the earth on the block. (f) It is smaller than the y-component of the force by the earth on the block. (g) It is larger than the y-component of the force by the earth on the block (h) None of the above. (vi) If the block moves at a constant speed, what could be true of the frictional force by the surface on the block? Circle the letter for ALL choices that apply (a) It could be zero. (b) It could be kinetic friction. (c) It could be static friction. (d) It could point straight left. (e) It could point straight right. (0 It could point straight up. (g) It could point straight down, (h) It could point down the incline. (i) It is equal to the coefficient of friction, μ. 0) It is definitely proportional to the Normal force. (k) It might be less than μN.
need help with this whole problem

Answer 1

yoo.uponent 七 en CD oh 4 Correct bption似(i) 7/u) f-ce By İhs farth on the block will be .zg a wani4 placed on Earth Su,fce . force ,daef, earth wil be Wa ma where body, g= acceleration due to But i tlus masc is on a inclinedt Sur face. The mature of Farth won't change & t will pull phe mg loody with same force downward mj

7.(Iİİ) For the given X-Y axis The components of tarth Force are mgcose & mgsing . Burb aloug x we have mysin e'」wSX68 V m Here FrRForie of Earth on the bo dy s mg So, long X-ais Fose of earth will be FERSino 7 liv) weight mass timas g 7 6) wken we put a body n wates. Tt drowns/ geer into water. But when put a bodly on tabla. tt doesn Sink into table bacause table offess Nosmal Force against booly The Normal foreis xpandi culax to the urface Hare, mgcose is eaual to Nokmal Force So, (o) is Correct. .7 (i) If the block moves at a nstant speed.mgNet F0γ ca macose on the block must be Zero.
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