how many mL of a 1.0M Cu(NO3)2 stock solution are required to prepare a 100mL 0.010M...

Question

Question

how many mL of a 1.0M Cu(NO3)2 stock solution are required to prepare a 100mL 0.010M Cu(NO3)2 solution

science chemistry

Answer 1

Answer #1

=> We know that. MY, Ma Vz Ca(NO3)2 Ca(NO3)2 M=1.0M M 2= 0.010m VE? N2 = 100ml => 1.0M XV, = 0.010 M X 100ML =) Vi = 0.010 mA

Answer 2

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