Question

Question Question 4 (2 marks) Attempt 1 A surface is described by the equation 2 =6x2+3y2. aR aR For a surface defined by a vector R(x,y)=(1,4,2(0,4)), the element of surface area is given by ds =( Jo Xāj dc dy. For the given surface, determine the cross product ƏR ƏR Jo taj Each component should be expressed using the correct Maple syntax; for example, one component might be: -31+7***exp(-11) The first component of the cross product is Skipped The second component of the cross product is Skipped The third component of the cross product is Skipped

Answer 1

ie Box, y) Soi Given a surface is described by the equation 2= 6x² + 3y² & Vector Rex, y) = (x, y, z6n,y)) =(x, y, G+3y² ait yg + (6 + 3y² on on (62 + 3y k = 1. i to. j + 12x (1, 0, 12x) = ² + 120k OR Ja 2x it ra SR da OR Jy Ja ЭУ lt ay Jt ay dy (63+34% o.it 1.3 + by =co, 1, 64) = 3 + by IR dy DR = (1, 0, 12x) (0, 1, by) 22 Jy > w L K O 122 6y - - Co- 128) } (by-o) + K (1-0) - 12x1 -6y + эR ax Х ar ay = (-122, -oy, 1) The first component of the cross product is – 12x. the second component of the cross product is – by the third component of the cross product is