Question

Replace the forces acting on the L-shaped bracket with the following force-couple systems. Neglect the thickness of the bar in your calculations. (Express the resultant forces in vector form in newtons.) 290 NA 190 mm 480N 190 mm cDE I 190 mm 190 mm 190 N (a) an equivalent force-couple system that acts at point A Indicate the magnitude in N.m and direction of the couple moment, magnitude Nm direction -Select- (b) an equivalent force-couple system that acts at point B FRED ) Indicate the magnitude in N.m and direction of the couple moment. magnitude N.m direction ---Select-- (c) an equivalent force-couple system that acts at point C FR=(D ) Indicate the magnitude in N.m and direction of the couple moment, magnitude N.m direction |--Select- (d) an equivalent force-couple system that acts at point D FR=(C ) Indicate the magnitude in N.m and direction of the couple moment. magnitude N.m direction --Select- (e) an equivalent force-couple system that acts at point E

Answer 1

२१ON 380 mm a 480 Sin 37 USON force acting on A = 6870 +UROCOs327+ ukopin U Derman E: 93.345+ 288.saſ Kinoman Yuso Cos 37 ky 190mm 1 TFAI = 93.345² + 288.872 = 303.58N YES

115) = 303.58 N Xo.380 MA = (480 Cos37 )+(480 sin 377 ) 37 +0.190 (Ach) MA = 200.56 (ACW) - 2900 AB 480 SIN370 Irrespective of position the force will remain same , -uson 480 C0537° TIFAI = IFB) = lfcl = 1F) = 1FE) = 303.58N) MB - (290 x0.19) + (U8O Sin 37 x0.19) + (U80 Cos 37 x0.19) MB = 189.82Nm

990N © Mc = (290 x0.38) + Culosin 37 xd Bosin37 uson 0 38 cr 480Goran Mc = 165.08 Nm) (Ach ) 0.10 MO = 290 80.38 NM 290N 0.35 MD = 110.2 Nm (AW) 480N 90N ME = 290x0.38 0.36 480S10370 -480xsin 39x0.19) ME = 55.31Nm 480605370 Koigt