Question

The two parallel wires have currents 11=34.0000A, and and 12 which are equal but run in opposite directions. The currents run in opposite directions as shown. The wires are 1.00m long and the mass of each wire is 0.001 kg. The magnetic force can hold up wire 1 against gravity if the distance between the wires is just right (called a current balance). What should the distance be to make wire 1 "float" against gravity? Your Answer:
Please, I need help with this question.

Answer 1

& Fg d 92 wire and gegroni laboral occolealdoring net Islame between two wires should be тр х 28 бол Дом гр. wire ® and I be current in wire 2 The Force on wire due to wore @ a lo I Izd la length of 2nd wird Force 1g achting upward tos permeablites as our current flows as free-space in two wire is an opposite direction so whore o emperorenced repeling froce due to wire Di man liten jasuon peoree fg = mg eme mass o of acts down word wire will froat top two forces are canal lio I, Izb 2Rd mg teo I. Iz l 2Ã mg distomoe 8houd be de 09023592m ATX 107 34 34 x 1 20.00 9.8 -7 2010 tx 342 0.001 49.8 23.592 x 103m 0.0 2 3 592 m m UVUD Scanned with CamScanner