Question

A converging lens (f = 20 cm) and a diverging lens (f = 30 cm) are placed 90 cm apart, and an object is placed 30 cm in front of the converging lens. Object's height is 2 cm. Find the location of the final image. Left Right Object 30 cm 90 cm fy=20 cm fz=30 cm O at infinity. O 60 cm away from lens 2 and on the right side of lens 2. 20 cm away from lens 2 and on the right side of lens 2. 15 cm away from lens 2 and on the left side of lens 2. O 60 cm away from lens 2 and on the left side of lens 2. 15 cm away from lens 2 and on the right side of lens 2. 20 cm away from lens 2 and on the left side of lens 2.

Answer 1

for convenging lens: f = + 20cm object distance dos applying lens ear to find the location of image due to 1st lens : = 30 cm ㅗ di, 5 do, - I 20 I+ 30 dir dii - 60cm So ist image will be furred at a distante Gocom Right of 1st lense,

Now this image will work as obyeet four second lens For second lens object distance dag = 90-60 = 30cm fq = -30cm PLEASE + ! UPVOTE fy dog die It 6 - I+I 30 dia - 30 dia -15 cm This is the final image location 15 cm left side of lenen Ans is option D 115cm lens 2 and from away, Jens 2. on the left side of