Question

please help with all parts

Consider the full-bridge inverter shown in Fig. P3.1 with an R-L load of R = 8 and L 30 mH, fo 60 Hz, and V 120 V. ST S1 + o (a) Determine the rms for vo and io for the first, third, fifth, and seventh harmonics. (b) Determine the total power delivered to the load for the above harmonics. (c) Carefully sketch the waveforms for vo and vs Label the sketches and show switches conduction pattern (d) Sketch the waveforms for is2 and io. Show the transistor and diode conduction pattern SA Fig. Pl.1 S

Answer 1

11:31 COL 211 60 % ore Vs = 120 Vg 110V for feill bridge in Verter = W@ Vime = 8.66 21 A © Irma ei ole 120 3fi11:3) Irms + * all switches Corbins aminti pulled diodes to conduct the Current in the I S. Sz Oppu dite direction 20 F apply looop opens Sig S3 when Sz, su are operated - Vo + vsi=0 svo --VS, = -Ve

for ve sau are wave Vocess é 4 Vs Sinet 106) is on Loiva sinfet +Ow) pot harmonica Nor = 4(120) Sin cat ... Voirns - 4620] [:: vemete htz ] Voims = 108.079 V Virms Zoi = 8+)11.369 2011 = 13.85 (54.726 Dyns arms 121 108.079 € 13.85 7.8035 A Por = voi io cos (vo, kol) Pos = 108.079 x 7.80 35 * Bus (54.725 ) Poi a 489.645 w 200 harmonic : 4 (120) 36.0260 Vos mm 03m 382 * 203 = 3+j11.31(3) = 32.86 76.73 103 = 36.026 = 1.0334 A 34.86 Po3 = (36.028) (1.0334). Gos (7673) Poz= 8.54 56 w

oth harmonic 4(1rol Vosrme 21.6158 V 5 TL 205 = 8411131(5): 57.113 181.94 Ios = 21.6158 -0.3784 A 57113 Pos = ().6159] (0.3734) Cos (81.94) Pos - 1.1468 W 15.44 V th harmonica 4 (120) Vorrms - 7 707= 8+; 1431672 = 79.33 36. 3 ? 107 = 1 sony = 0.1946 A 79.33 Port = (15.44) (0.1946) cos (36.38 ) Poz: 0.1897 w Total Power for 1, 3, 517 harmonics Py = but Post Post Pos = 487.045+ 8.5456€ 1.1468 + 0.1897 Pq = 4,96.9271 W

A A I/2 l t 1. " QI :D . Q3 . Du 'QL / D3 : isr p isaatio when S2, Sy Conducta