Question

File:EORI Nore This is just ample, the below. This best shows the pres best may lost other p o sarily included in the e rve of details expected spoloms. 1 15 Det Sample Test #2 the stat if the 1/sample Test #2 - Peoblum 1 #include <iostream using neapace std: , Tot 14 -, Tota15 - Lot Totall . Tota12-0, Totals for (i = -7/ 3 7 ++) Totall ++: for (9-11. -111- 3) for (9-1; 100 ) for k = 1 5 k+) for ( - 1; ) j++) Tata14++ for ( 1) K B : 2) Eee 4 -9 > 3-9) for ( 12 ) Total5++ cout << "\nTotalt - Total « trota12 - << "\nTotal = " << Total << Tota14 = << intetals =" << Totals << endl Tota 12 << Total Problem Outro: Totall- Total

Answer 1

Ans:-

Syntax:-

for(initialization;condition;flow statement)

{

}

Code:-

for(j = -7; j<=7 ; j++)//no of iterations = 15 {-7,-6,-5,-4,-3,-2,-1,0,1,2,3,4,5,6,7}
Total1++;

This loop runs from j =-7 to j = 7 insteps of increment of 1 of j

and Total1 increment by 1 in each iteration

Total1 = number of iteration = 15

j value while condition	Total1
-7	0->1
-6	1->2
-5	2->3
-4	3->4
-3	4->5
-2	5->6
-1	6->7
0	7->8
1	8->9
2	9->10
3	10->11
4	11->12
5	12->13
6	13->14
7	14->15
8(exit while)

Total1 = 15

Code:-

for(j = 11; j>-11 ; j-=3)// no of iteration = 8 {11,8,5,2,-1,-4,-7,-10}
Total2+=2;

in each iteration Total2 increment by 2

Total2 = 2 x no of iteration = 2 x 8 =16

j	Total2
11->8	0->2
8->5	2->4
5->2	4->6
2->-1	6->8
-1->-4	8->10
-4->-7	10->12
-7->-10	12->14
-10->-13	14->16
-13!>-11 exit while

Total2 = 16

Code:-

for(j = 1; j<=100 ; j*=3) // no of iteration =5 {1,3,9,27,81}
Total3+=j;

j	Total3
1->3	0->1
3->9	1->4
9->27	4->13
27->81	13->40
81->243	40->121
243!<=100 exit while

Total3 = 121

Code:-

for(k = 1; k<=5 ; k++)// no of iterations = 5 {1, 2, 3, 4, 5}
for(j=1;j<=k; j++)// no of iterations = k
Total4++;

in Nested for loop,

total iteration = 1+2+3+4+5

total iteration = 15

in each iteration , Total4 increment by one.

Total4 = 15

k value	1->2	2->3	3->4	4->5	5->6	6!<=5(exit while)
iteration of inner loop	1	1->2	1->2->3	1->2->3->4	1->2->3->4->5
Total4 value	0->1	1->2->3	3->4->5->6	6->7->8->9->10	10->11->12->13->14->15

Total4 = 15

Code:-

for(k = 1; k<=8 ; k+=2)//no of iteration = 4 {1, 3 , 5 , 7}
for(j=9;j>0;j+=-2)  )//no of iteration = 5 {9, 7 , 5 , 4, 2}
for(m = 4 ;m<=12 ;m += 4)  //no of iteration = 3 {4, 8 ,12}
Total5++;

If number of iterations are fixed for each loop,

Total iteration = Iteration of first loop x Iteration of second loop x Iteration of third loop

Total iterations = 4 x 5 x 3 = 60

In each iteration Total5 increment by 1

Total5 = number of iterations = 60

Total1 = 15

Total2 = 16

Total3 = 121

Total4 = 15

Total5 = 60

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