Question

vue in o nours, 33 minutes. Due Tue 03/17/2020 11:59 pm For the curve defined by F(t) = (e-4, 5t, e') find the unit tangent vector, unit normal vector, normal acceleration, and tangential acceleration at t = 2. Preview Preview Ī (t) = Ñ (t) = ar = an = Preview Preview License Points possible: 1 This is attempt 1 of 5. Submit

Answer 1

Ans: Given Curve Y(t) = {et, st, et> o since, Unit tangent vector is 17'(tul tres are the i (t) = 'et ) = L-et, siet> val=1 #141)= -e-ty?? (s)*+6e4j2 - Vet25teit A litl= √25+624tpat (41= <-et, s, et> I et 25 26 ata 24 25+ P te (asteattpat 9 P © Unit normal vector is LÝ () = 7t). 171411 retraset les te eten 125 test pat - 5 e se F'it) - set*lext) 2settzeit ! (este?t test) 9/2 (as te te 2) / 25 to 2 port -26 pital de ) (care 20 te

/ (-zet aset² I (as te 24 p2t)} asett (84€,,2 (256t+aet) 2 (aste the 2673 . (asteatteat) 3 45 2 + = 4e +100+6lse + 25 e le 4e +10o +62 1 402 100+63seat as eth (At, ²7 4 624/ 100+625 eet (as te att pat 3 Perlonge alonge parter 4 400 629p2+ +62962t & asett (e46, 32+200 (asteatte2+)3 1629224 6296?tė A+(2588tsoettas ) +200 (aste2t + p2t)} I 62922++6294-2 osett-so é + zse-44200 (aste-2t eat)3 7 629e2t+629 e 2tt asettaasettiso (aste att p2tl3 Presl = 629(e27 e 2t) +25(e462144) +150 (aste 24 ezt)3 cos(esc") 3(esc" ) 150

-seat (est) (aste-24 p 2t j 3/2 Net) / rettaset Vastet p2t (aste-24 p2t) 629(eztzett) +33 (e46é 4t) +150 (25te at test) 629(ez te=24)+25(244245 +150 (aste 24 feet)3 2seart Was tettert (as te ett puht) 629(edte ) +29(447e4t) +150 (asteet eat 3 i NCH) - / (peétaset) 629 (224-224) +25(84422-4t) +150 629(eatte-zt) +25(e46e-4€) +150 come -se?(141) _ (629 (4242 2t)+25 (et e ) +190) Ź persones , (ze 4 25e!) f029664 € 46,425[***) +150 629(e?47826) +25 (ett ett) +150 se tase -se Pe +39 wien para (semet, selet), ticket) < zeitaset, -seitfeat) , ze teset) .: (t) = 5 /629(e24+p?t) + 25(efttett) + 150

☺ ) Q = *'[+). ř'ct) act). I'(t) * | | | | Q = cct) - ta : tu act) - 1"(t) = +"(+) since, tous <etst, et > verzice) - K-étis, et > a(t) = Vict) = ri(t) = <et, o, et> Cit). f(t) =/ -eat de-to-face o promet Leat -e ſaste-2 tpat aste-2t ezt ni At = <- é?to eat > √ asteatteet

© Wro Normal acceleration, an= 1 ft) x 7"(t) I Iri(t) | Ect) x acts | lucts I Jc xãct) = let set o et - il seto) -5 (--2°)+(o-se*) = set itaj"-se tanto et : V (t) x 2 (t) =< set, a,-set> | fit) 1 = √25+8=24&pat an= < se, ai-set> Jestett test et

The Ñ (E) Unit tangent vector fit) Unit normal vector Tangendicel acceleration at cet t= 2 and Normal cecceleration is F(t)= - <-ét, s,et > - V 2s +62t+eht N (t)= - <ae taset, -seit(evt,), ze taset > 5629(ezetett) + 25(ettent) +150 a at t=2 at <-et ,o,et> Tas et tet AN=- <set, 2,-set> √25 te-attest