Question

4) Provide an appropriate response. 4) The area under the standard normal curve between 1 and 2 is equal to 0.1359. Scores on a particular aptitude test are normally distributed with a mean of 100 and a standard deviation of 10. Which of the following are equal to 13.59%? a. The percentage of scores between 120 and 130 b. The percentage of scores between 110 and 120 c. The percentage of scores between 80 and 90 d. The percentage of scores between 90 and 120 e. The percentage of scores between 90 and 110 В) b Ae C) b, c D) a, b Provide an appropriate response. Assume that the variable under consideration has a density curve. 5) The area under the density curve that lies to the right of 17 is 0.470. What percentage of all possible observations of the variable are at most 17? A) 72% B) 47% C) 53% D) 28% 5)

Answer 1

solution: .(4) . Given that * Mean - 100 * SD © = 10. * normal curve between cand a is equal 0.1359. we find which of following caual 13.59% z score for 1 S erie - Mt 10 3 100+(1x10) z score z Score for a 100 +(2410) -190. for "-11 : 100 -(110) 090 for "-2" 100-(2 XD) - z score 3. The percentage of scores between 110 and 120 © The Percentage of scorey be turen 80 and 120 Bic' is correct (5) we find observa hions of varible are at most l¥. I here right of it is 0.470. '= -0.490 . 0:53 100 let Opkom Wer is correct