The heat of combustion of sucrose is approximately 5,650 KJ/mol. Convert this number to Kcal/gram.

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Question

science chemistry

Answer 1

Answer #1

Sucrose Mot= 3433 9mo) mol 3 2.3 G KJ= O.239 ka = 565 mol KJ 5o 65 rmo 342.39 O 239 Ka X 5 65 K KT 342.39 56a XO 2 39 0 00392

Answer 2

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