Question

solve al the subsections step by step please!

(Dead. 2144 (down) Rook Love: +Cdowa)... . (wind : ?/et (up only) - .. 20k wid s (can act in either direction .. a CI-2500 in . . I-56Dint Rigid Connections at B and c. Pinned Connections at A and D. Frame ABCD carries the service and wind loads shown above. dead, roof live, (as Compute the maximum positive and negative bendin moments at midspan of beam BC wnder factored loods... (6) Compute the maximum positive and negative bending moments at end B of beam BC under factored Toads. (6) Compute the maximum exial tension and compression in column AB under the tored be € Amig (ml)

Answer 1

Gfuen Dead 2ktt () Root 1Pue: 4 K/ft ) wind 2 KIft (1 LOK wind C 12500 fo 4 10' I S00o fn Rgid connection PRnned comnection. At eC At A &D sotutons 1Ove) Total load on ec pootion, (taki 4 kips /At 4+2-2 -0.33 Kips/in factored lo ad Be beam, ore 0.33 x s=0. 495 Ki/ fu O5 Kips/

Reactions uequtibriumeg 0 PS RA tRD 7-S 0.S X1S E MA-O a.Sx15 X IS 20x 10 Kips (t) RD -17.083 - 3.583 kfps

frem supes positn theorem, 0.S kips (n Cfactered lead) 0g.583 kips 17.083 kips ag.s83kips 20kips 17083 kips t0' D 201Kips J.583 Kips ps 17.083 moment at mid pf e endiny tapty a section at di'stauce fremc let AL MaX - 0:52 Mr= 7.083x 17.083 X 7. S Max. Poeitine 6.M. at idl spau 0SX 7.5 X 7 5 2 - 114.06 kips- F kips-t Nerative B. H. at id spau Max

ey B. M at 2 Me 2 17.083 x i-0.5 x 1S 159.995 deo kips- ft May. Positive BM. at B kips- ft O kips f jehive Max e> Maxfm um axfal teusion Rn celomn AL .583 8ps Max qxial compresien o kips