Question

1. The angled beam supports a triangular distributed load and a concentrated force as shown. Determine the reactions at the pin support (A) and at the roller support (B). Start your analysis presenting the adequate FBD. Solutions without FBD will be graded F 400 N 600 N/m 3 m 70° 35° as zero. (50 pts.) 3 m 60 3 m F- 844.643 N RAX--937.57N 53. 99N

the top picture has the correct answers, the bottom picture is my attempt. could you tell me where I went wrong with the sum of forces?

Answer 1

Coo F: MON FON It will be 30 Degree AX 7 Ay {Fx; Ax + 1800 cos(60) - 400 cos(70)- No cost.ss) {fy; Ay - 1800sin (60)-400 sin (20) + Nosin(sse) (-1800. 4)+(400 cos (70). 6sm(60)) + (-400 ron (70)-6) + (Nosness ). 9) + ( No cos(ss). 6 sin (60) No = 844.6N Ax=279 N 3 wao Ay = 1243N J

Grohm Furon 10 im 3 tan boo 2 tem 60- F = 2 x 600 x 2560 F = 900 - 1800N Coco A 2 Ficasso 4x costs - Cosbe V Fisinborst 600 (20560°)Y Zesho = 2m F Entó Ficas 2 м B Rosinas 3m Fcosto Fisino- RBCas35° 2 tengo" quote 60 2m EMA=0 CROCOs35)*(9) +RB 8m35) + (3 tambo) + (FC870)x(3 tem 60)-(F&nzolye - (F cos60)x (2) (Fi&n Go) x (2 ton 60)=0

7.372 Ro+ 2.980 RB + EX1,797 - Fx 5.638 - Fixi- Fix320 10.352 RB + 400 x1, 777 - Uno x s. 638 - 18 no x1 - 1800 x3 =0 TRB=844.706N E Fnzo) – Ant Fisin6o- F Costo - RB 5135=0 Ana 180x 3 - 400x 0.342 - 844.70 6X 0.574 An= 937.5 34 N (A) { fyzo; Ay-Ficasso - F sinto tRo 10835=0 Ag = 1800 Cess0 + 40 Sinto- 844.766 cos35 [Ay = 583.934N (1)