Is this recursive function?
Given two functions T1(n) = 20n and T2(n) = n2 +10n−200 and assuming integer n > 0,
what is the minimum value of n such that T1(n) < T2(n)?
Homework Answers
Answer:
T1(n) = 20n
T2(n) = n2 + 10n - 200
T1(n) < T2(n)
20n < n2 + 10n - 200
n2 - 20n - 200 > 0
(x - 27.32)(x + 7.32) > 0
SO, x > 27.32 or x > -7.32
But, since x > 0,
The minimum value of x for T1(n) < T2(n) is 27
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