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Electricity

Hello, I'd like to check if my answers are correct. For figure 1, I have to solve for the current, voltage in R5, and power. And for the second one, it is as indicated.

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Electrical-Engineering   electricity   
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Answer #1

a. V1 at R1, we have It = 2A and applying ohms law. V = IR, 

V1 = ItR1 = 2A(5ohms) = 10V

b. V2 = ItR2 = 2A(5ohms) = 10V

c. appying KVL to the loop V - V1 - V2 = 0

V = V1 + V2 = 10V + 10V = 20V

d. P1 = It2 R1 = 22(5) = 20W

e. P2 = IV = 2A(10V) = 20W

f. series resistors are added. Rt = R1 + R2 = 5 + 5 = 10ohms

g. Pt = IV = 2(20) = 40W 

answered by: Dingani
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