Question

Using C programming

Using the supplied example code as a starting point, add 3 more conversions using strtod(). Make sure you change the output conversion for type double. Use the same input strings and base codes as the strtol() function example but notice how the numbers are now represented. Manipulate the width and precision as needed for a good presentation.  

Supplied code:

#include <stdio.h>

#include <string.h>

int main(void)

{

long num;

char* ptr;

num = strtol("12345 Decimal Constant: ", &ptr, 0);

printf("%s \t%ld\n", ptr, num);

num = strtol("11001 Binary Constant: ", &ptr, 2);

printf("%s \t%ld\n", ptr, num);

num = strtol("13572 123 Octal Constant: ", &ptr, 8);

printf("%s \t%ld\n", ptr, num);

//put your conversions here

return 0;

}//end main

Answer 1

#include <stdio.h>

#include <string.h>

int main(void)

{

long num;
double d;

char* ptr;

num = strtol("12345 Decimal Constant: ", &ptr, 0);

printf("%s \t%ld\n", ptr, num);

num = strtol("11001 Binary Constant: ", &ptr, 2);

printf("%s \t%ld\n", ptr, num);

num = strtol("13572 123 Octal Constant: ", &ptr, 8);

printf("%s \t%ld\n", ptr, num);

//put your conversions here

d = strtod("12345.0 Decimal Constant: ", &ptr, 0);

printf("%s \t%lf\n", ptr, d);

d = strtod("11001.0 Binary Constant: ", &ptr, 2);

printf("%s \t%lf\n", ptr, d);

d = strtod("13572 123 Octal Constant: ", &ptr, 8);

printf("%s \t%lf\n", ptr, d);

return 0;

}//end main

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