A 17.0 g piece of aluminum (which has a molar heat capacity of 24.03 J/°C·mol) is heated to 82.4°C and dropped into a calorimeter containing water (specific heat capacity of water is 4.18 J/g°C) initially at 22.3°C. The final temperature of the water is 25.3°C. Ignoring significant figures, calculate the mass of water in the calorimeter.
heat lost by Al = heat gained by water
qAl = qwater
mC(
T)
= mC(
T)
CAl = 24.03 J/0C . mol = 0.89 J/0C g
17.0 x 0.89 (82.4 - 25.3) = m x 4.18 x (25.3 - 22.3)
863.923 = 12.54 m
m = 68.90 g
mass of water = 68.90 g
A 17.0 g piece of aluminum (which has a molar heat capacity of 24.03 J/°C·mol) is...
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both questions please
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