Question

A solid cylindrical conductor is supported by insulating disks on the axis of a conducting tube with outer radius Ra = 5.85 cm and inner radius Rb = 4.75 cm . (Figure 1) The central conductor and the conducting tube carry equal currents of I = 1.35 A in opposite directions. The currents are distributed uniformly over the cross sections of each conductor. What is the value of the magnetic field at a distance r = 4.99 cm from the axis of the conducting tube?

Part C

What is the value of the magnetic field at a distance r = 4.99 cm from the axis of the conducting tube? Recall that μ0=4π×10−7 T⋅m/A.

Answer 1

Now while b 〈 r c we will have an enclosed current of - と(r) 1- (b such that (을) yielding 2 2TT 1

Let inner radius b = 4.75 cm

and outer radius c = 5.85 cm

r = 4.99 cm

I = 1.35 A

So, B = (2*10^-7*1.35/0.0499)*(1 – 0.728)/(1 – 0.66) = 4.33*10^-6 T